Under construction still
(testing that math works here) ddx(∫0xf(u),du)=f(x) ddx(∫g(x)h(x)f(u),du)=f(h(x))h′(x)−f(g(x))g′(x) \begin{align*} \frac{d}{dx} \left( \int_{0}^{x} f(u) , du \right) &= f(x) \ \frac{d}{dx} \left( \int_{g(x)}^{h(x)} f(u) , du \right) &= f(h(x))h'(x) - f(g(x))g'(x) \end{align*} dxd(∫0xf(u),du)=f(x) dxd(∫g(x)h(x)f(u),du)=f(h(x))h′(x)−f(g(x))g′(x)